Angles · CM-AN-5050-5

Aluminum Equal Angle 50 × 50 × 5 mm

Specification

CM-AN-5050-5 is a 50 × 50 × 5 mm equal aluminum angle in 6063-T5. It weighs 1.286 kg/m with a cross-sectional area of 476.3 mm², and moments of inertia Ix = 11.21 cm⁴ and Iy = 11.21 cm⁴, calculated from the nominal section at 2.70 g/cm³.

01 Section drawing5050
02 Extruded product 50 × 50 × 5 mm equal aluminum angle, clear anodized — CharMax CM-AN-5050-5
CM-AN-5050-5Design drawing → finished profile · mm6063-T5

01Dimensions

DimensionValue
Leg A50 mm
Leg B50 mm
Thickness5 mm

02Section properties

PropertyValue
Cross-sectional area476.3 mm²
Weight (2.70 g/cm³)1.286 kg/m
Moment of inertia Ix11.21 cm⁴
Moment of inertia Iy11.21 cm⁴
Outside perimeter197 mm

Nominal values calculated from the standard cross-section at 2.70 g/cm³; Ix and Iy about the centroidal axes. The drawing issued with your quotation confirms final values.

03Supply and processing

ItemStandard
Alloy and temper6063-T5; other 6000-series alloys on request
LengthsMill lengths (typically 6 m) or cut to length
FinishesMill, anodized or powder coated
TolerancesEN 755-9 or ANSI H35.2, as specified
FabricationCutting, drilling, tapping, CNC machining
DocumentsMaterial certificate; dimensional report on request

04Questions

How do you calculate aluminum angle weight?

For an equal angle, area ≈ t × (2A − t) in mm², plus a small amount for the root fillet; multiply by 0.0027 for kg per metre.

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